Difference between revisions of "TDSM 5.3"

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m (binomial distribution, normal)
 
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(a) <math>B(100, 0.5) \approx N(100 \times 0.5, 100 \times 0.5 \times 0.5) = N(50, 25)</math>  
 
(a) <math>B(100, 0.5) \approx N(100 \times 0.5, 100 \times 0.5 \times 0.5) = N(50, 25)</math>  
  
<math>P(X \geq 70) =  1 - P(X < 70) =  1 - P \left( Z < \frac{70-50}{25} \right) = 1 - P(Z<4) \approx 0</math>
+
<math>P(X \geq 70) =  1 - P(X < 70) =  1 - P \left( Z < \frac{70-50}{\sqrt{25}} \right) = 1 - P(Z<4) \approx 0</math>

Latest revision as of 00:43, 13 December 2017

(a) [math]B(100, 0.5) \approx N(100 \times 0.5, 100 \times 0.5 \times 0.5) = N(50, 25)[/math]

[math]P(X \geq 70) = 1 - P(X \lt 70) = 1 - P \left( Z \lt \frac{70-50}{\sqrt{25}} \right) = 1 - P(Z\lt 4) \approx 0[/math]