Difference between revisions of "TDSM 2.9"

From The Data Science Design Manual Wikia
Jump to: navigation, search
(Created page with "When all terms <math> x_0 = x_1 = \dots = x_{n-1} </math> The arthmetic mean is <math>\frac{1}{n} \sum_{i = 0}^{n-1} = \frac{1}{n}\times nx_0</math>")
 
 
(One intermediate revision by the same user not shown)
Line 1: Line 1:
 
When all terms <math> x_0 = x_1 = \dots = x_{n-1} </math>
 
When all terms <math> x_0 = x_1 = \dots = x_{n-1} </math>
  
The arthmetic mean is <math>\frac{1}{n} \sum_{i = 0}^{n-1} = \frac{1}{n}\times nx_0</math>
+
The arthmetic mean is <math>\frac{1}{n} \sum_{i = 0}^{n-1} = \frac{1}{n}\cdot x_0 = x_0</math>
 +
 
 +
The geometric mean is <math> \sqrt[n]{\prod_{i = 0}^{n-1}} = \sqrt[n]{x_0 ^n}  = x_0</math>
 +
 
 +
So the arithmetic mean equals the geometric mean when all terms are the same.

Latest revision as of 18:48, 11 September 2017

When all terms [math] x_0 = x_1 = \dots = x_{n-1} [/math]

The arthmetic mean is [math]\frac{1}{n} \sum_{i = 0}^{n-1} = \frac{1}{n}\cdot x_0 = x_0[/math]

The geometric mean is [math] \sqrt[n]{\prod_{i = 0}^{n-1}} = \sqrt[n]{x_0 ^n} = x_0[/math]

So the arithmetic mean equals the geometric mean when all terms are the same.